18x^2+27x-2=-12

Solution for 18x^2+27x-2=-12 equation:

18x^2+27x-2=-12

We move all terms to the left:

18x^2+27x-2-(-12)=0

We add all the numbers together, and all the variables

18x^2+27x+10=0

a = 18; b = 27; c = +10;
Δ = b2-4ac
Δ = 272-4·18·10
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-3}{2*18}=\frac{-30}{36}
=-5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+3}{2*18}=\frac{-24}{36}
=-2/3
$